What is the integral of 20cos(x)e^{-2x} ?

The integral of 20cos(x)e^{-2x} is 20((e^{-2x}sin(x))/5-(2e^{-2x}cos(x))/5)+C

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integral of 20cos(x)e^{-2x}

\int 20 cos (x) e^{- 2 x} d x

20 (\frac{e ^{- 2 x} sin ( x )}{5} - \frac{2 e ^{- 2 x} cos ( x )}{5}) + C

Solution steps

\int 20 cos (x) e^{- 2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \int cos (x) e^{- 2 x} d x

Apply Integration By Parts

: e^{- 2 x} sin (x) - \int - 2 e^{- 2 x} sin (x) d x

= 20 (e^{- 2 x} sin (x) - \int - 2 e^{- 2 x} sin (x) d x)

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 (e^{- 2 x} sin (x) - (- 2 \cdot \int e^{- 2 x} sin (x) d x))

Apply Integration By Parts

: - e^{- 2 x} cos (x) - \int 2 e^{- 2 x} cos (x) d x

= 20 (e^{- 2 x} sin (x) - (- 2 (- e^{- 2 x} cos (x) - \int 2 e^{- 2 x} cos (x) d x)))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 (e^{- 2 x} sin (x) - (- 2 (- e^{- 2 x} cos (x) - 2 \cdot \int e^{- 2 x} cos (x) d x)))

Therefore

20 \cdot \int e^{- 2 x} cos (x) d x = 20 (e^{- 2 x} sin (x) - (- 2 (- e^{- 2 x} cos (x) - 2 \cdot \int e^{- 2 x} cos (x) d x)))

Isolate

\int e^{- 2 x} cos (x) d x

= 20 (\frac{e ^{- 2 x} sin ( x )}{5} - \frac{2 e ^{- 2 x} cos ( x )}{5})

Add a constant to the solution

= 20 (\frac{e ^{- 2 x} sin ( x )}{5} - \frac{2 e ^{- 2 x} cos ( x )}{5}) + C

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What is the integral of 20cos(x)e^{-2x} ?
The integral of 20cos(x)e^{-2x} is 20((e^{-2x}sin(x))/5-(2e^{-2x}cos(x))/5)+C