What is the integral of 9/(xln(6x)) ?

The integral of 9/(xln(6x)) is 9ln|ln(6x)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 9/(xln(6x))

\int \frac{9}{x ln ( 6 x )} d x

9 ln ∣ ln (6 x) ∣ + C

Solution steps

\int \frac{9}{x ln ( 6 x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int \frac{1}{x ln ( 6 x )} d x

Apply u-substitution

: \int \frac{1}{u ln ( u )} d u

= 9 \cdot \int \frac{1}{u ln ( u )} d u

Apply u-substitution

: \int \frac{1}{v} d v

= 9 \cdot \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= 9 ln ∣ v ∣

Substitute back

= 9 ln ∣ ln (6 x) ∣

Add a constant to the solution

= 9 ln ∣ ln (6 x) ∣ + C

\int \frac{4}{3 + 2 x} d x

\int e^{- (x - a)} d x

\int e^{x} cos (x) d x

\int s + t d s

\int \frac{5 x + 3 - x sec ^{2} ( x )}{x} d x

What is the integral of 9/(xln(6x)) ?
The integral of 9/(xln(6x)) is 9ln|ln(6x)|+C