What is the integral of 1/(9\sqrt[9]{x^8)} ?

The integral of 1/(9\sqrt[9]{x^8)} is \sqrt[9]{x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(9\sqrt[9]{x^8)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= \frac{1}{9} \cdot \int \frac{1}{x ^{\frac{8}{9}}} d x

Apply the Power Rule

: 9 x^{\frac{1}{9}}

= \frac{1}{9} \cdot 9 x^{\frac{1}{9}}

Simplify

Add a constant to the solution

\int \frac{3 x ^{4} + 8 x ^{3} - 5 x ^{2} + 2}{4 x ^{2}} d x

\int sin (6 x - 5) d x

\int - \frac{1}{( 1 + x ) ^{2}} d x

\int cos (e^{x}) d e^{e^{x}}

\int \frac{x ^{3}}{9 x ^{2} + 16} d x

What is the integral of 1/(9\sqrt[9]{x^8)} ?
The integral of 1/(9\sqrt[9]{x^8)} is \sqrt[9]{x}+C