What is the integral of (y^2sqrt(y)) ?

The integral of (y^2sqrt(y)) is 2/7 y^{7/2}+C

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integral of (y^2sqrt(y))

\int (y^{2} y) d y

\frac{2}{7} y^{\frac{7}{2}} + C

Solution steps

\int y^{2} y d y

Simplify

y^{2} y : y^{\frac{5}{2}}

= \int y^{\frac{5}{2}} d y

Apply the Power Rule

: \frac{2}{7} y^{\frac{7}{2}}

= \frac{2}{7} y^{\frac{7}{2}}

Add a constant to the solution

= \frac{2}{7} y^{\frac{7}{2}} + C

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What is the integral of (y^2sqrt(y)) ?
The integral of (y^2sqrt(y)) is 2/7 y^{7/2}+C