What is the integral of (5x^4+6x+3) ?

The integral of (5x^4+6x+3) is x^5+3x^2+3x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (5x^4+6x+3)

\int (5 x^{4} + 6 x + 3) d x

x^{5} + 3 x^{2} + 3 x + C

Solution steps

\int 5 x^{4} + 6 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{4} d x + \int 6 x d x + \int 3 d x

\int 5 x^{4} d x = x^{5}

\int 6 x d x = 3 x^{2}

\int 3 d x = 3 x

= x^{5} + 3 x^{2} + 3 x

Add a constant to the solution

= x^{5} + 3 x^{2} + 3 x + C

\int - \frac{cos ( x )}{sin ^{4} ( x )} d x

\int x (x^{2} - 2)^{15} d x

\int (\frac{cos ( x )}{sin ( x )})^{2} d x

\int \frac{x + 2}{x ( x ^{2} + 4 )} d x

\int 24 sin^{7} (3 x) cos^{3} (3 x) d x

What is the integral of (5x^4+6x+3) ?
The integral of (5x^4+6x+3) is x^5+3x^2+3x+C