What is the integral of (cos(x))/(sqrt(9-4sin^2(x))) ?

The integral of (cos(x))/(sqrt(9-4sin^2(x))) is 1/2 arcsin(2/3 sin(x))+C

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integral of (cos(x))/(sqrt(9-4sin^2(x)))

\int \frac{cos ( x )}{9 - 4 sin ^{2} ( x )} d x

\frac{1}{2} arcsin (\frac{2}{3} sin (x)) + C

Solution steps

\int \frac{cos ( x )}{9 - 4 sin ^{2} ( x )} d x

Apply u-substitution

: \int \frac{1}{9 - 4 u ^{2}} d u

= \int \frac{1}{9 - 4 u ^{2}} d u

Apply Trigonometric Substitution

: \int \frac{1}{2} d v

= \int \frac{1}{2} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 1 d v

Integral of a constant:

\int a d x = a x

= \frac{1}{2} \cdot 1 \cdot v

Substitute back

= \frac{1}{2} \cdot 1 \cdot arcsin (\frac{2}{3} sin (x))

Simplify

= \frac{1}{2} arcsin (\frac{2}{3} sin (x))

Add a constant to the solution

= \frac{1}{2} arcsin (\frac{2}{3} sin (x)) + C

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What is the integral of (cos(x))/(sqrt(9-4sin^2(x))) ?
The integral of (cos(x))/(sqrt(9-4sin^2(x))) is 1/2 arcsin(2/3 sin(x))+C