What is the integral of 4x-3sec(x)tan(x) ?

The integral of 4x-3sec(x)tan(x) is 2x^2-3sec(x)+C

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integral of 4x-3sec(x)tan(x)

\int 4 x - 3 sec (x) tan (x) d x

2 x^{2} - 3 sec (x) + C

Solution steps

\int 4 x - 3 sec (x) tan (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x d x - \int 3 sec (x) tan (x) d x

\int 4 x d x = 2 x^{2}

\int 3 sec (x) tan (x) d x = 3 sec (x)

= 2 x^{2} - 3 sec (x)

Add a constant to the solution

= 2 x^{2} - 3 sec (x) + C

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What is the integral of 4x-3sec(x)tan(x) ?
The integral of 4x-3sec(x)tan(x) is 2x^2-3sec(x)+C