What is the integral of \sqrt[3]{x^3} ?

The integral of \sqrt[3]{x^3} is (x^2)/2+C

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integral of \sqrt[3]{x^3}

\frac{x ^{2}}{2} + C

Solution steps

assuming

x \geq 0

= \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= \frac{x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{2}}{2} + C

\int 4 x^{3} - x d x

\int \frac{8 x ^{2} + x}{( 16 x ^{3} + 3 x ^{2} ) ^{2}} d x

\int (4 x^{2} - 3)^{2} d x

\int \frac{2 x ^{4} - 2 x ^{3} + x + 1}{x ^{3} - x ^{2}} d x

\int \frac{1}{( 1 - x ^{2} ) x ^{2}} d x

What is the integral of \sqrt[3]{x^3} ?
The integral of \sqrt[3]{x^3} is (x^2)/2+C