What is the integral of sec(4w)tan(4w) ?

The integral of sec(4w)tan(4w) is 1/4 sec(4w)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sec(4w)tan(4w)

\int sec (4 w) tan (4 w) d w

\frac{1}{4} sec (4 w) + C

Solution steps

\int sec (4 w) tan (4 w) d w

Apply u-substitution

: \int \frac{1}{4} d u

= \int \frac{1}{4} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{4} u

Substitute back

u = sec (4 w)

= \frac{1}{4} sec (4 w)

Add a constant to the solution

= \frac{1}{4} sec (4 w) + C

\int \frac{1}{3 cos ^{2} ( x ) + 1} d x

\int \frac{16 x ^{3}}{x ^{4} + 9} d x

\int \frac{csc ^{2} ( \frac{π}{x} )}{x ^{2}} d x

\int (cos (x) cos (y) - cot (x)) d x

\int e^{- t} cos (π t) d t

What is the integral of sec(4w)tan(4w) ?
The integral of sec(4w)tan(4w) is 1/4 sec(4w)+C