What is the integral of 7ye^{4y^2} ?

The integral of 7ye^{4y^2} is 7/8 e^{4y^2}+C

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integral of 7ye^{4y^2}

\int 7 y e^{4 y^{2}} d y

\frac{7}{8} e^{4 y^{2}} + C

Solution steps

\int 7 y e^{4 y^{2}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int y e^{4 y^{2}} d y

Apply u-substitution

: \int \frac{e ^{u}}{8} d u

= 7 \cdot \int \frac{e ^{u}}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \frac{1}{8} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 7 \cdot \frac{1}{8} e^{u}

Substitute back

u = 4 y^{2}

= 7 \cdot \frac{1}{8} e^{4 y^{2}}

Simplify

7 \cdot \frac{1}{8} e^{4 y^{2}} : \frac{7}{8} e^{4 y^{2}}

= \frac{7}{8} e^{4 y^{2}}

Add a constant to the solution

= \frac{7}{8} e^{4 y^{2}} + C

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What is the integral of 7ye^{4y^2} ?
The integral of 7ye^{4y^2} is 7/8 e^{4y^2}+C