What is the integral of p(p+4)^7 ?

The integral of p(p+4)^7 is 1/18 (p+4)^8(2p-1)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of p(p+4)^7

\int p (p + 4)^{7} d p

\frac{1}{18} (p + 4)^{8} (2 p - 1) + C

Solution steps

\int p (p + 4)^{7} d p

Apply u-substitution

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int u^{\frac{2}{7}} d u = \frac{7}{9} u^{\frac{9}{7}}

= \frac{1}{7} (\frac{7}{9} u^{\frac{9}{7}} - \frac{7}{2} u^{\frac{8}{7}})

Substitute back

u = (p + 4)^{7}

= \frac{1}{7} (\frac{7}{9} ((p + 4)^{7})^{\frac{9}{7}} - \frac{7}{2} ((p + 4)^{7})^{\frac{8}{7}})

Simplify

\frac{1}{7} (\frac{7}{9} ((p + 4)^{7})^{\frac{9}{7}} - \frac{7}{2} ((p + 4)^{7})^{\frac{8}{7}}) : \frac{1}{18} (p + 4)^{8} (2 p - 1)

= \frac{1}{18} (p + 4)^{8} (2 p - 1)

Add a constant to the solution

= \frac{1}{18} (p + 4)^{8} (2 p - 1) + C

\int \frac{1}{u ^{8}} d u

\int x (x + 1) (x + 2) d x

\int \frac{1}{sin ( \frac{x}{2} ) cos ( \frac{x}{2} )} d x

\int (x + \frac{5}{2}) e^{x^{2} + 5 x + 1} d x

\int tan^{2} (z) sec (z) d z

What is the integral of p(p+4)^7 ?
The integral of p(p+4)^7 is 1/18 (p+4)^8(2p-1)+C