What is the integral of 4x[x^2+5]^3 ?

The integral of 4x[x^2+5]^3 is 1/2 (x^2+5)^4+C

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integral of 4x[x^2+5]^3

\int 4 x [x^{2} + 5]^{3} d x

\frac{1}{2} (x^{2} + 5)^{4} + C

Solution steps

\int 4 x [x^{2} + 5]^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x [x^{2} + 5]^{3} d x

Simplify

(x^{2} + 5)^{3} : (x^{2} + 5)^{2} (x^{2} + 5)

= 4 \cdot \int x (x^{2} + 5)^{2} (x^{2} + 5) d x

Simplify

x (x^{2} + 5)^{2} (x^{2} + 5) : x (x^{2} + 5)^{3}

= 4 \cdot \int x (x^{2} + 5)^{3} d x

Apply u-substitution

: \int \frac{u ^{3}}{2} d u

= 4 \cdot \int \frac{u ^{3}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{2} \cdot \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= 4 \cdot \frac{1}{2} \cdot \frac{u ^{4}}{4}

Substitute back

u = x^{2} + 5

= 4 \cdot \frac{1}{2} \cdot \frac{( x ^{2} + 5 ) ^{4}}{4}

Simplify

4 \cdot \frac{1}{2} \cdot \frac{( x ^{2} + 5 ) ^{4}}{4} : \frac{1}{2} (x^{2} + 5)^{4}

= \frac{1}{2} (x^{2} + 5)^{4}

Add a constant to the solution

= \frac{1}{2} (x^{2} + 5)^{4} + C

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What is the integral of 4x[x^2+5]^3 ?
The integral of 4x[x^2+5]^3 is 1/2 (x^2+5)^4+C