What is the integral of 1/(3+sin(2x)) ?

The integral of 1/(3+sin(2x)) is 1/(2sqrt(2))arctan(1/(2sqrt(2))(3tan(x)+1))+C

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integral of 1/(3+sin(2x))

\int \frac{1}{3 + sin ( 2 x )} d x

\frac{1}{2 2} arctan (\frac{1}{2 2} (3 tan (x) + 1)) + C

Solution steps

\int \frac{1}{3 + sin ( 2 x )} d x

Apply u-substitution

: \int \frac{1}{2 ( 3 + sin ( u ) )} d u

= \int \frac{1}{2 ( 3 + sin ( u ) )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{3 + sin ( u )} d u

Apply u-substitution

: \int \frac{2}{3 ( 1 + v ^{2} ) + 2 v} d v

= \frac{1}{2} \cdot \int \frac{2}{3 ( 1 + v ^{2} ) + 2 v} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot 2 \cdot \int \frac{1}{3 ( 1 + v ^{2} ) + 2 v} d v

Complete the square

3 (1 + v^{2}) + 2 v : 3 (v + \frac{1}{3})^{2} + \frac{8}{3}

= \frac{1}{2} \cdot 2 \cdot \int \frac{1}{3 ( v + \frac{1}{3} ) ^{2} + \frac{8}{3}} d v

Apply u-substitution

: \int \frac{3}{9 w ^{2} + 8} d w

= \frac{1}{2} \cdot 2 \cdot \int \frac{3}{9 w ^{2} + 8} d w

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot 2 \cdot 3 \cdot \int \frac{1}{9 w ^{2} + 8} d w

Apply Integral Substitution

= \frac{1}{2} \cdot 2 \cdot 3 \cdot \int \frac{1}{6 2 ( t ^{2} + 1 )} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot 2 \cdot 3 \cdot \frac{1}{6 2} \cdot \int \frac{1}{t ^{2} + 1} d t

Use the common integral:

\int \frac{1}{t ^{2} + 1} d t = arctan (t)

= \frac{1}{2} \cdot 2 \cdot 3 \cdot \frac{1}{6 2} arctan (t)

Substitute back

= \frac{1}{2} \cdot 2 \cdot 3 \cdot \frac{1}{6 2} arctan (\frac{3}{2 2} (tan (\frac{2 x}{2}) + \frac{1}{3}))

Simplify

\frac{1}{2} \cdot 2 \cdot 3 \cdot \frac{1}{6 2} arctan (\frac{3}{2 2} (tan (\frac{2 x}{2}) + \frac{1}{3})) : \frac{1}{2 2} arctan (\frac{1}{2 2} (3 tan (x) + 1))

= \frac{1}{2 2} arctan (\frac{1}{2 2} (3 tan (x) + 1))

Add a constant to the solution

= \frac{1}{2 2} arctan (\frac{1}{2 2} (3 tan (x) + 1)) + C

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What is the integral of 1/(3+sin(2x)) ?
The integral of 1/(3+sin(2x)) is 1/(2sqrt(2))arctan(1/(2sqrt(2))(3tan(x)+1))+C