What is the integral of 8x^{1/3}+10x^{-1/3} ?

The integral of 8x^{1/3}+10x^{-1/3} is 6x^{4/3}+15x^{2/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 8x^{1/3}+10x^{-1/3}

\int 8 x^{\frac{1}{3}} + 10 x^{- \frac{1}{3}} d x

6 x^{\frac{4}{3}} + 15 x^{\frac{2}{3}} + C

Solution steps

\int 8 x^{\frac{1}{3}} + 10 x^{- \frac{1}{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{\frac{1}{3}} d x + \int 10 x^{- \frac{1}{3}} d x

\int 8 x^{\frac{1}{3}} d x = 6 x^{\frac{4}{3}}

\int 10 x^{- \frac{1}{3}} d x = 15 x^{\frac{2}{3}}

= 6 x^{\frac{4}{3}} + 15 x^{\frac{2}{3}}

Add a constant to the solution

= 6 x^{\frac{4}{3}} + 15 x^{\frac{2}{3}} + C

\int (ln (y) - 2) d y

\int cos (3 - x) d x

\int π (e^{x})^{2} d x

\int \frac{5}{x ^{2} + 2 x} d x

\int \frac{3 x ^{3} + x}{( x ^{2} + 1 ) ^{2}} d x

What is the integral of 8x^{1/3}+10x^{-1/3} ?
The integral of 8x^{1/3}+10x^{-1/3} is 6x^{4/3}+15x^{2/3}+C