What is the integral of 4xsqrt(x-9) ?

The integral of 4xsqrt(x-9) is 4(2/5 (x-9)^{5/2}+6(x-9)^{3/2})+C

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integral of 4xsqrt(x-9)

\int 4 x x - 9 d x

4 (\frac{2}{5} (x - 9)^{\frac{5}{2}} + 6 (x - 9)^{\frac{3}{2}}) + C

Solution steps

\int 4 x x - 9 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x x - 9 d x

Apply u-substitution

: \int (u + 9) u d u

= 4 \cdot \int (u + 9) u d u

Expand

(u + 9) u : u^{\frac{3}{2}} + 9 u

= 4 \cdot \int u^{\frac{3}{2}} + 9 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 4 (\int u^{\frac{3}{2}} d u + \int 9 u d u)

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int 9 u d u = 6 u^{\frac{3}{2}}

= 4 (\frac{2}{5} u^{\frac{5}{2}} + 6 u^{\frac{3}{2}})

Substitute back

u = x - 9

= 4 (\frac{2}{5} (x - 9)^{\frac{5}{2}} + 6 (x - 9)^{\frac{3}{2}})

Add a constant to the solution

= 4 (\frac{2}{5} (x - 9)^{\frac{5}{2}} + 6 (x - 9)^{\frac{3}{2}}) + C

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What is the integral of 4xsqrt(x-9) ?
The integral of 4xsqrt(x-9) is 4(2/5 (x-9)^{5/2}+6(x-9)^{3/2})+C