What is the integral of x^5+2sqrt(x) ?

The integral of x^5+2sqrt(x) is (x^6)/6+4/3 x^{3/2}+C

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integral of x^5+2sqrt(x)

\int x^{5} + 2 x d x

\frac{x ^{6}}{6} + \frac{4}{3} x^{\frac{3}{2}} + C

Solution steps

\int x^{5} + 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{5} d x + \int 2 x d x

\int x^{5} d x = \frac{x ^{6}}{6}

\int 2 x d x = \frac{4}{3} x^{\frac{3}{2}}

= \frac{x ^{6}}{6} + \frac{4}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{x ^{6}}{6} + \frac{4}{3} x^{\frac{3}{2}} + C

\int (e^{2}) d x

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\int \frac{4 x - arctan ^{3} ( x )}{1 + x ^{2}} d x

What is the integral of x^5+2sqrt(x) ?
The integral of x^5+2sqrt(x) is (x^6)/6+4/3 x^{3/2}+C