What is the integral of sin^7(x/6)cos(x/6) ?

The integral of sin^7(x/6)cos(x/6) is 3/4 sin^8(x/6)+C

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integral of sin^7(x/6)cos(x/6)

\int sin^{7} (\frac{x}{6}) cos (\frac{x}{6}) d x

\frac{3}{4} sin^{8} (\frac{x}{6}) + C

Solution steps

\int sin^{7} (\frac{x}{6}) cos (\frac{x}{6}) d x

Apply u-substitution

: \int \frac{6 7 u}{7} d u

= \int \frac{6 7 u}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{6}{7} \cdot \int 7 u d u

Apply the Power Rule

: \frac{7}{8} u^{\frac{8}{7}}

= \frac{6}{7} \cdot \frac{7}{8} u^{\frac{8}{7}}

Substitute back

u = sin^{7} (\frac{x}{6})

= \frac{6}{7} \cdot \frac{7}{8} (sin^{7} (\frac{x}{6}))^{\frac{8}{7}}

Simplify

\frac{6}{7} \cdot \frac{7}{8} (sin^{7} (\frac{x}{6}))^{\frac{8}{7}} : \frac{3}{4} sin^{8} (\frac{x}{6})

= \frac{3}{4} sin^{8} (\frac{x}{6})

Add a constant to the solution

= \frac{3}{4} sin^{8} (\frac{x}{6}) + C

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What is the integral of sin^7(x/6)cos(x/6) ?
The integral of sin^7(x/6)cos(x/6) is 3/4 sin^8(x/6)+C