What is the integral of 12x+sin(x) ?

The integral of 12x+sin(x) is 6x^2-cos(x)+C

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integral of 12x+sin(x)

\int 12 x + sin (x) d x

6 x^{2} - cos (x) + C

Solution steps

\int 12 x + sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x d x + \int sin (x) d x

\int 12 x d x = 6 x^{2}

\int sin (x) d x = - cos (x)

= 6 x^{2} - cos (x)

Add a constant to the solution

= 6 x^{2} - cos (x) + C

\int \frac{1}{sin ( x ) ( 2 + cos ( x ) )} d x

\int \frac{1}{x ( in x ) ^{2} + 9} d x

\int (1 - x) d x

\int \frac{x}{( x ^{2} - 2 x + 3 )} d x

\int (x^{2} - 2 x)^{5} (x - 1) d x

What is the integral of 12x+sin(x) ?
The integral of 12x+sin(x) is 6x^2-cos(x)+C