What is the integral of (-6)/(sqrt(x)) ?

The integral of (-6)/(sqrt(x)) is -12sqrt(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (-6)/(sqrt(x))

\int \frac{- 6}{x} d x

- 12 x + C

Solution steps

\int \frac{- 6}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= - 6 \cdot 2 x^{\frac{1}{2}}

Simplify

- 6 \cdot 2 x^{\frac{1}{2}} : - 12 x

= - 12 x

Add a constant to the solution

= - 12 x + C

\int 16 x (8 x^{2} + 5)^{2} d x

\int x^{2} 64 - x^{3} d x

\int \frac{1}{36 - 9 x ^{2}} d x

\int \frac{1}{x ln ( 2 x )} d x

\int x^{9} cos (x^{10}) d x

What is the integral of (-6)/(sqrt(x)) ?
The integral of (-6)/(sqrt(x)) is -12sqrt(x)+C