What is the integral of (3x)/(sqrt(1+x^2)) ?

The integral of (3x)/(sqrt(1+x^2)) is 3sqrt(1+x^2)+C

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integral of (3x)/(sqrt(1+x^2))

\int \frac{3 x}{1 + x ^{2}} d x

3 1 + x^{2} + C

Solution steps

\int \frac{3 x}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x}{1 + x ^{2}} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= 3 \cdot \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{2} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= 3 \cdot \frac{1}{2} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = 1 + x^{2}

= 3 \cdot \frac{1}{2} \cdot 2 (1 + x^{2})^{\frac{1}{2}}

Simplify

3 \cdot \frac{1}{2} \cdot 2 (1 + x^{2})^{\frac{1}{2}} : 3 1 + x^{2}

= 3 1 + x^{2}

Add a constant to the solution

= 3 1 + x^{2} + C

\int 2 x^{2} (x - 2) d x

\int \frac{( x + 3 ) ^{4}}{2 x} d x

\int \frac{x + 2}{x ^{2} - 4 x + 4} d x

What is the integral of (3x)/(sqrt(1+x^2)) ?
The integral of (3x)/(sqrt(1+x^2)) is 3sqrt(1+x^2)+C