What is the integral of ((x^3-2))/(x^2+1) ?

The integral of ((x^3-2))/(x^2+1) is 1/2 (x^2+1-ln|x^2+1|)-2arctan(x)+C

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integral of ((x^3-2))/(x^2+1)

\int \frac{( x ^{3} - 2 )}{x ^{2} + 1} d x

\frac{1}{2} (x^{2} + 1 - ln x^{2} + 1) - 2 arctan (x) + C

Solution steps

\int \frac{x ^{3} - 2}{x ^{2} + 1} d x

Expand

\frac{x ^{3} - 2}{x ^{2} + 1} : \frac{x ^{3}}{x ^{2} + 1} - \frac{2}{x ^{2} + 1}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{3}}{x ^{2} + 1} d x - \int \frac{2}{x ^{2} + 1} d x

\int \frac{x ^{3}}{x ^{2} + 1} d x = \frac{1}{2} (x^{2} + 1 - ln x^{2} + 1)

\int \frac{2}{x ^{2} + 1} d x = 2 arctan (x)

= \frac{1}{2} (x^{2} + 1 - ln x^{2} + 1) - 2 arctan (x)

Add a constant to the solution

= \frac{1}{2} (x^{2} + 1 - ln x^{2} + 1) - 2 arctan (x) + C

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What is the integral of ((x^3-2))/(x^2+1) ?
The integral of ((x^3-2))/(x^2+1) is 1/2 (x^2+1-ln|x^2+1|)-2arctan(x)+C