What is the integral of (-7+9/(sqrt(p))) ?

The integral of (-7+9/(sqrt(p))) is -7p+18sqrt(p)+C

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integral of (-7+9/(sqrt(p)))

\int (- 7 + \frac{9}{p}) d p

- 7 p + 18 p + C

Solution steps

\int - 7 + \frac{9}{p} d p

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 7 d p + \int \frac{9}{p} d p

\int 7 d p = 7 p

\int \frac{9}{p} d p = 18 p

= - 7 p + 18 p

Add a constant to the solution

= - 7 p + 18 p + C

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What is the integral of (-7+9/(sqrt(p))) ?
The integral of (-7+9/(sqrt(p))) is -7p+18sqrt(p)+C