What is the integral of x(7x^2+5)^9 ?

The integral of x(7x^2+5)^9 is 1/140 (7x^2+5)^{10}+C

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integral of x(7x^2+5)^9

\int x (7 x^{2} + 5)^{9} d x

\frac{1}{140} (7 x^{2} + 5)^{10} + C

Solution steps

\int x (7 x^{2} + 5)^{9} d x

Apply u-substitution

: \int \frac{u ^{9}}{14} d u

= \int \frac{u ^{9}}{14} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{14} \cdot \int u^{9} d u

Apply the Power Rule

: \frac{u ^{10}}{10}

= \frac{1}{14} \cdot \frac{u ^{10}}{10}

Substitute back

u = 7 x^{2} + 5

= \frac{1}{14} \cdot \frac{( 7 x ^{2} + 5 ) ^{10}}{10}

Simplify

\frac{1}{14} \cdot \frac{( 7 x ^{2} + 5 ) ^{10}}{10} : \frac{1}{140} (7 x^{2} + 5)^{10}

= \frac{1}{140} (7 x^{2} + 5)^{10}

Add a constant to the solution

= \frac{1}{140} (7 x^{2} + 5)^{10} + C

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What is the integral of x(7x^2+5)^9 ?
The integral of x(7x^2+5)^9 is 1/140 (7x^2+5)^{10}+C