What is the integral of x^{-1.65} ?

The integral of x^{-1.65} is -(1.53846…)/(x^{0.65)}+C

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integral of x^{-1.65}

\int x^{- 1.65} d x

- \frac{1.53846 \dots}{x ^{0.65}} + C

Solution steps

\int x^{- 1.65} d x

Apply the Power Rule

: - \frac{1.53846 \dots}{x ^{0.65}}

= - \frac{1.53846 \dots}{x ^{0.65}}

Add a constant to the solution

= - \frac{1.53846 \dots}{x ^{0.65}} + C

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What is the integral of x^{-1.65} ?
The integral of x^{-1.65} is -(1.53846…)/(x^{0.65)}+C