What is the integral of (x^2)/(x^2+49) ?

The integral of (x^2)/(x^2+49) is -7arctan(x/7)+x+C

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integral of (x^2)/(x^2+49)

\int \frac{x ^{2}}{x ^{2} + 49} d x

- 7 arctan (\frac{x}{7}) + x + C

Solution steps

\int \frac{x ^{2}}{x ^{2} + 49} d x

\frac{x ^{2}}{x ^{2} + 49} = - \frac{49}{x ^{2} + 49} + 1

= \int - \frac{49}{x ^{2} + 49} + 1 d x

Apply Integral Substitution

= \int 7 (- \frac{1}{u ^{2} + 1} + 1) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int - \frac{1}{u ^{2} + 1} + 1 d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 7 (- \int \frac{1}{u ^{2} + 1} d u + \int 1 d u)

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

\int 1 d u = u

= 7 (- arctan (u) + u)

Substitute back

u = \frac{x}{7}

= 7 (- arctan (\frac{x}{7}) + \frac{x}{7})

Simplify

7 (- arctan (\frac{x}{7}) + \frac{x}{7}) : - 7 arctan (\frac{x}{7}) + x

= - 7 arctan (\frac{x}{7}) + x

Add a constant to the solution

= - 7 arctan (\frac{x}{7}) + x + C

\int 21 x^{2} - 12 x - 5 d x

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What is the integral of (x^2)/(x^2+49) ?
The integral of (x^2)/(x^2+49) is -7arctan(x/7)+x+C