What is the integral of (sec(x))^2tan(x) ?

The integral of (sec(x))^2tan(x) is (tan^2(x))/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (sec(x))^2tan(x)

\int (sec (x))^{2} tan (x) d x

\frac{tan ^{2} ( x )}{2} + C

Solution steps

\int (sec (x))^{2} tan (x) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = tan (x)

= \frac{tan ^{2} ( x )}{2}

Add a constant to the solution

= \frac{tan ^{2} ( x )}{2} + C

\int e^{- 0.4 t} d t

\int \frac{3 cos ( x )}{1 + cos ( x )} d x

\int \frac{- 6}{1 - x ^{2}} d x

\int \frac{x - 1}{3} d x

\int \frac{tan ( x ) + sin ( x )}{cos ( x )} d x

What is the integral of (sec(x))^2tan(x) ?
The integral of (sec(x))^2tan(x) is (tan^2(x))/2+C