What is the integral of 1/(y^{5/2)} ?

The integral of 1/(y^{5/2)} is -2/(3y^{3/2)}+C

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integral of 1/(y^{5/2)}

\int \frac{1}{y ^{\frac{5}{2}}} d y

- \frac{2}{3 y ^{\frac{3}{2}}} + C

Solution steps

\int \frac{1}{y ^{\frac{5}{2}}} d y

Apply the Power Rule

: - \frac{2}{3 y ^{\frac{3}{2}}}

= - \frac{2}{3 y ^{\frac{3}{2}}}

Add a constant to the solution

= - \frac{2}{3 y ^{\frac{3}{2}}} + C

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What is the integral of 1/(y^{5/2)} ?
The integral of 1/(y^{5/2)} is -2/(3y^{3/2)}+C