What is laplacetransform-5e^{4t} ?

The answer to laplacetransform-5e^{4t} is -5/(s-4)

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laplacetransform-5e^{4t}

laplace transform

- 5 e^{4 t}

- \frac{5}{s - 4}

Solution steps

L {- 5 e^{4 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {e^{4 t}}

L {e^{4 t}} : \frac{1}{s - 4}

= - 5 \cdot \frac{1}{s - 4}

Refine

- 5 \frac{1}{s - 4} : - \frac{5}{s - 4}

= - \frac{5}{s - 4}

\frac{\partial}{\partial x} (x sin (2 x^{2} y))

\int \frac{1}{t 4 t ^{2} - 1} d t

y^{^{''}} - y = x^{2} e^{x}

\int 2 (x - 1) d x

y^{^{''}} + 2 y^{^{'}} + 36 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is laplacetransform-5e^{4t} ?
The answer to laplacetransform-5e^{4t} is -5/(s-4)