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Popular >

integral of 1/(u+2)

Solution

\int \frac{1}{u + 2} d u

Solution

ln ∣ u + 2 ∣ + C

Solution steps

\int \frac{1}{u + 2} d u

Apply u-substitution

: \int \frac{1}{v} d v

= \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= ln ∣ v ∣

Substitute back

v = u + 2

= ln ∣ u + 2 ∣

Add a constant to the solution

= ln ∣ u + 2 ∣ + C

Popular Examples

integral of (x^3+1)/(x(x^2+1)^2)

\int \frac{x ^{3} + 1}{x ( x ^{2} + 1 ) ^{2}} d x

integral of sqrt(5+2x^2)

\int 5 + 2 x^{2} d x

integral of (2x+1)/(2x^2+x-1)

\int \frac{2 x + 1}{2 x ^{2} + x - 1} d x

integral of-5xsin(x^2)

\int - 5 x sin (x^{2}) d x

integral of (28)/(1+16x^2)

\int \frac{28}{1 + 16 x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(u+2) ?
The integral of 1/(u+2) is ln|u+2|+C