What is the integral of (-7+9/(sqrt(x))) ?

The integral of (-7+9/(sqrt(x))) is -7x+18sqrt(x)+C

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integral of (-7+9/(sqrt(x)))

\int (- 7 + \frac{9}{x}) d x

- 7 x + 18 x + C

Solution steps

\int - 7 + \frac{9}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 7 d x + \int \frac{9}{x} d x

\int 7 d x = 7 x

\int \frac{9}{x} d x = 18 x

= - 7 x + 18 x

Add a constant to the solution

= - 7 x + 18 x + C

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What is the integral of (-7+9/(sqrt(x))) ?
The integral of (-7+9/(sqrt(x))) is -7x+18sqrt(x)+C