What is the integral of x^2-11x+28 ?

The integral of x^2-11x+28 is (x^3)/3-(11x^2)/2+28x+C

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integral of x^2-11x+28

\int x^{2} - 11 x + 28 d x

\frac{x ^{3}}{3} - \frac{11 x ^{2}}{2} + 28 x + C

Solution steps

\int x^{2} - 11 x + 28 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 11 x d x + \int 28 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 11 x d x = \frac{11 x ^{2}}{2}

\int 28 d x = 28 x

= \frac{x ^{3}}{3} - \frac{11 x ^{2}}{2} + 28 x

Add a constant to the solution

= \frac{x ^{3}}{3} - \frac{11 x ^{2}}{2} + 28 x + C

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What is the integral of x^2-11x+28 ?
The integral of x^2-11x+28 is (x^3)/3-(11x^2)/2+28x+C