What is (\partial)/(\partial x)(z/(1+z^2y^2)) ?

The answer to (\partial)/(\partial x)(z/(1+z^2y^2)) is 0

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(\partial)/(\partial x)(z/(1+z^2y^2))

\frac{\partial}{\partial x} (\frac{z}{1 + z ^{2} y ^{2}})

0

Solution steps

\frac{\partial}{\partial x} (\frac{z}{1 + z ^{2} y ^{2}})

Treat

z, y

as constants

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d}{d x} (A x e^{3 x})

f (t) = sin (t) - t cos (t)

f^{^{'}} (x) = \frac{1 - e ^{x}}{9 + e ^{x}}

x y^{^{'}} + y = - 2 x y^{2}, y (1) = 2

\frac{\partial}{\partial y} (y^{2} sin (x y))

What is (\partial)/(\partial x)(z/(1+z^2y^2)) ?
The answer to (\partial)/(\partial x)(z/(1+z^2y^2)) is 0