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Popular >

integral of (t-1)

Solution

\int (t - 1) d t

Solution

\frac{t ^{2}}{2} - t + C

Solution steps

\int t - 1 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int t d t - \int 1 d t

\int t d t = \frac{t ^{2}}{2}

\int 1 d t = t

= \frac{t ^{2}}{2} - t

Add a constant to the solution

= \frac{t ^{2}}{2} - t + C

Graph

Popular Examples

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\int u (t) d t

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\int 2 x^{2} (x - 2) (4 x - 5) d x

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\int x^{2} cos (10 x) d x

integral of ((x+2))/((x+1)^2)

\int \frac{( x + 2 )}{( x + 1 ) ^{2}} d x

integral of ((e^x)^2-2)/(e^{2x)}

\int \frac{( e ^{x} ) ^{2} - 2}{e ^{2 x}} d x

Frequently Asked Questions (FAQ)

What is the integral of (t-1) ?
The integral of (t-1) is (t^2)/2-t+C