What is the integral of 2^{x-2} ?

The integral of 2^{x-2} is (2^{x-2})/(ln(2))+C

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integral of 2^{x-2}

\int 2^{x - 2} d x

\frac{2 ^{x - 2}}{ln ( 2 )} + C

Solution steps

\int 2^{x - 2} d x

Simplify

2^{x - 2} : 2^{x} \cdot 2^{- 2}

= \int 2^{x} \cdot 2^{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2^{- 2} \cdot \int 2^{x} d x

2^{- 2} = \frac{1}{4}

= \frac{1}{4} \cdot \int 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{1}{4} \cdot \frac{2 ^{x}}{ln ( 2 )}

Simplify

\frac{1}{4} \cdot \frac{2 ^{x}}{ln ( 2 )} : \frac{2 ^{x - 2}}{ln ( 2 )}

= \frac{2 ^{x - 2}}{ln ( 2 )}

Add a constant to the solution

= \frac{2 ^{x - 2}}{ln ( 2 )} + C

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What is the integral of 2^{x-2} ?
The integral of 2^{x-2} is (2^{x-2})/(ln(2))+C