What is the integral of e^{a+bx} ?

The integral of e^{a+bx} is 1/b e^{a+bx}+C

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integral of e^{a+bx}

\int e^{a + b x} d x

\frac{1}{b} e^{a + b x} + C

Solution steps

\int e^{a + b x} d x

Apply u-substitution

: \int \frac{e ^{u}}{b} d u

= \int \frac{e ^{u}}{b} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{b} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{b} e^{u}

Substitute back

u = a + b x

= \frac{1}{b} e^{a + b x}

Add a constant to the solution

= \frac{1}{b} e^{a + b x} + C

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