What is the integral of sin^8(x/7)cos(x/7) ?

The integral of sin^8(x/7)cos(x/7) is 7/9 sin^9(x/7)+C

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integral of sin^8(x/7)cos(x/7)

\int sin^{8} (\frac{x}{7}) cos (\frac{x}{7}) d x

\frac{7}{9} sin^{9} (\frac{x}{7}) + C

Solution steps

\int sin^{8} (\frac{x}{7}) cos (\frac{x}{7}) d x

Apply u-substitution

: \int sin^{8} (u) cos (u) \cdot 7 d u

= \int sin^{8} (u) cos (u) \cdot 7 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int sin^{8} (u) cos (u) d u

Apply u-substitution

: \int v^{8} d v

= 7 \cdot \int v^{8} d v

Apply the Power Rule

: \frac{v ^{9}}{9}

= 7 \cdot \frac{v ^{9}}{9}

Substitute back

= 7 \cdot \frac{sin ^{9} ( \frac{x}{7} )}{9}

Simplify

7 \cdot \frac{sin ^{9} ( \frac{x}{7} )}{9} : \frac{7}{9} sin^{9} (\frac{x}{7})

= \frac{7}{9} sin^{9} (\frac{x}{7})

Add a constant to the solution

= \frac{7}{9} sin^{9} (\frac{x}{7}) + C

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What is the integral of sin^8(x/7)cos(x/7) ?
The integral of sin^8(x/7)cos(x/7) is 7/9 sin^9(x/7)+C