What is the integral of (sin(3x)+cos(5x)) ?

The integral of (sin(3x)+cos(5x)) is -1/3 cos(3x)+1/5 sin(5x)+C

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integral of (sin(3x)+cos(5x))

\int (sin (3 x) + cos (5 x)) d x

- \frac{1}{3} cos (3 x) + \frac{1}{5} sin (5 x) + C

Solution steps

\int sin (3 x) + cos (5 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (3 x) d x + \int cos (5 x) d x

\int sin (3 x) d x = - \frac{1}{3} cos (3 x)

\int cos (5 x) d x = \frac{1}{5} sin (5 x)

= - \frac{1}{3} cos (3 x) + \frac{1}{5} sin (5 x)

Add a constant to the solution

= - \frac{1}{3} cos (3 x) + \frac{1}{5} sin (5 x) + C

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What is the integral of (sin(3x)+cos(5x)) ?
The integral of (sin(3x)+cos(5x)) is -1/3 cos(3x)+1/5 sin(5x)+C