What is the integral of 3e^{-2x+10}-3 ?

The integral of 3e^{-2x+10}-3 is -3/2 e^{-2x+10}-3x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3e^{-2x+10}-3

\int 3 e^{- 2 x + 10} - 3 d x

- \frac{3}{2} e^{- 2 x + 10} - 3 x + C

Solution steps

\int 3 e^{- 2 x + 10} - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 e^{- 2 x + 10} d x - \int 3 d x

\int 3 e^{- 2 x + 10} d x = - \frac{3}{2} e^{- 2 x + 10}

\int 3 d x = 3 x

= - \frac{3}{2} e^{- 2 x + 10} - 3 x

Add a constant to the solution

= - \frac{3}{2} e^{- 2 x + 10} - 3 x + C

\int sin (x) - 6 cos (x) d x

\int (\frac{1}{x ^{2} + 2 x}) d x

\int 4 x^{2} (4 x - 5)^{2} d x

\int \frac{2 x}{x ^{3} - 4 x} d x

sin (π x)

What is the integral of 3e^{-2x+10}-3 ?
The integral of 3e^{-2x+10}-3 is -3/2 e^{-2x+10}-3x+C