What is the integral of sin(2t)sin(t) ?

The integral of sin(2t)sin(t) is 2/3 sin^3(t)+C

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integral of sin(2t)sin(t)

\int sin (2 t) sin (t) d t

\frac{2}{3} sin^{3} (t) + C

Solution steps

\int sin (2 t) sin (t) d t

Rewrite using trig identities

= \int 2 sin^{2} (t) cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin^{2} (t) cos (t) d t

Apply u-substitution

: \int u^{2} d u

= 2 \cdot \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= 2 \cdot \frac{u ^{3}}{3}

Substitute back

u = sin (t)

= 2 \cdot \frac{sin ^{3} ( t )}{3}

Simplify

2 \cdot \frac{sin ^{3} ( t )}{3} : \frac{2}{3} sin^{3} (t)

= \frac{2}{3} sin^{3} (t)

Add a constant to the solution

= \frac{2}{3} sin^{3} (t) + C

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What is the integral of sin(2t)sin(t) ?
The integral of sin(2t)sin(t) is 2/3 sin^3(t)+C