What is the integral of 1/(x(ln(x^4))) ?

The integral of 1/(x(ln(x^4))) is 1/4 ln(4|ln(x)|)+C

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integral of 1/(x(ln(x^4)))

\int \frac{1}{x ( ln ( x ^{4} ) )} d x

\frac{1}{4} ln (4 ∣ ln (x) ∣) + C

Solution steps

\int \frac{1}{x ln ( x ^{4} )} d x

Apply u-substitution

: \int \frac{1}{4 u ln ( u )} d u

= \int \frac{1}{4 u ln ( u )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{1}{u ln ( u )} d u

Apply u-substitution

: \int \frac{1}{v} d v

= \frac{1}{4} \cdot \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= \frac{1}{4} ln ∣ v ∣

Substitute back

= \frac{1}{4} ln ln (x^{4})

Simplify

\frac{1}{4} ln ln (x^{4}) : \frac{1}{4} ln (4 ∣ ln (x) ∣)

= \frac{1}{4} ln (4 ∣ ln (x) ∣)

Add a constant to the solution

= \frac{1}{4} ln (4 ∣ ln (x) ∣) + C

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What is the integral of 1/(x(ln(x^4))) ?
The integral of 1/(x(ln(x^4))) is 1/4 ln(4|ln(x)|)+C