What is the integral of 2x-2sin(x) ?

The integral of 2x-2sin(x) is x^2+2cos(x)+C

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integral of 2x-2sin(x)

\int 2 x - 2 sin (x) d x

x^{2} + 2 cos (x) + C

Solution steps

\int 2 x - 2 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x d x - \int 2 sin (x) d x

\int 2 x d x = x^{2}

\int 2 sin (x) d x = - 2 cos (x)

= x^{2} - (- 2 cos (x))

Simplify

= x^{2} + 2 cos (x)

Add a constant to the solution

= x^{2} + 2 cos (x) + C

\int x (x - 2)^{2} - x d x

\int (x^{2} ln (x) + 1) d x

\int \frac{x + 1}{( x + 3 ) ^{2}} d x

\int 0.8 e^{x} d x

\int \frac{7}{( 2 x ) ^{5}} d x

What is the integral of 2x-2sin(x) ?
The integral of 2x-2sin(x) is x^2+2cos(x)+C