What is the integral from 1 to 4 of 1/(sqrt(x)) ?

The integral from 1 to 4 of 1/(sqrt(x)) is 2

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integral from 1 to 4 of 1/(sqrt(x))

\int_{1}^{4} \frac{1}{x} d x

2

Solution steps

\int_{1}^{4} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{1}^{4}

= [2 x^{\frac{1}{2}}]_{1}^{4}

Apply radical rule:

= [2 x]_{1}^{4}

Compute the boundaries:

2

= 2

\frac{\partial}{\partial x} (arcsin (x yz))

\int \frac{x ^{3}}{( 5 - x ^{4} ) ^{6}} d x

\frac{d y}{d x} = - x y

\int_{0}^{2 π} cos^{2} (6 x) d x

\frac{\partial}{\partial x} (2 x^{3} + 3 y^{2} - 6 x y + 2)

What is the integral from 1 to 4 of 1/(sqrt(x)) ?
The integral from 1 to 4 of 1/(sqrt(x)) is 2