What is the integral of sin(2x-7) ?

The integral of sin(2x-7) is -1/2 cos(2x-7)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin(2x-7)

\int sin (2 x - 7) d x

- \frac{1}{2} cos (2 x - 7) + C

Solution steps

\int sin (2 x - 7) d x

Apply u-substitution

: \int sin (u) \frac{1}{2} d u

= \int sin (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{2} (- cos (u))

Substitute back

u = 2 x - 7

= \frac{1}{2} (- cos (2 x - 7))

Simplify

= - \frac{1}{2} cos (2 x - 7)

Add a constant to the solution

= - \frac{1}{2} cos (2 x - 7) + C

\int 4 x e^{4 x^{2}} d x

\int 4 x^{2} + 144 x^{4} d x

\int - 12 x^{2} d x

\int ln (\frac{x}{k}) d x

\int 2 x^{3} x^{2} + 4 d x

What is the integral of sin(2x-7) ?
The integral of sin(2x-7) is -1/2 cos(2x-7)+C