What is the integral of e^te^{e^t} ?

The integral of e^te^{e^t} is e^{e^t}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^te^{e^t}

\int e^{t} e^{e^{t}} d t

e^{e^{t}} + C

Solution steps

\int e^{t} e^{e^{t}} d t

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = e^{t}

= e^{e^{t}}

Add a constant to the solution

= e^{e^{t}} + C

\int (1 - cos^{2} (2 x)) d x

\int \frac{x ^{7}}{( 6 - x ^{8} ) ^{2}} d x

\int \frac{6}{x ^{5}} d x

\int 5^{- 2 x + 1} d x

\int y^{2} e^{- 3 y} d y