What is the integral of 1/(sqrt(y^3)) ?

The integral of 1/(sqrt(y^3)) is -2/(sqrt(y))+C

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integral of 1/(sqrt(y^3))

\int \frac{1}{y ^{3}} d y

- \frac{2}{y} + C

Solution steps

\int \frac{1}{y ^{3}} d y

Apply exponent rule:

(a^{n})^{m} = a^{n \cdot m}

y^{3} = y^{\frac{3}{2}}

= \int \frac{1}{y ^{\frac{3}{2}}} d y

Apply the Power Rule

: - \frac{2}{y}

= - \frac{2}{y}

Add a constant to the solution

= - \frac{2}{y} + C

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What is the integral of 1/(sqrt(y^3)) ?
The integral of 1/(sqrt(y^3)) is -2/(sqrt(y))+C