What is the integral of ((x-1))/(24) ?

The integral of ((x-1))/(24) is 1/24 ((x^2)/2-x)+C

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integral of ((x-1))/(24)

\int \frac{( x - 1 )}{24} d x

\frac{1}{24} (\frac{x ^{2}}{2} - x) + C

Solution steps

\int \frac{x - 1}{24} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{24} \cdot \int x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{24} (\int x d x - \int 1 d x)

\int x d x = \frac{x ^{2}}{2}

\int 1 d x = x

= \frac{1}{24} (\frac{x ^{2}}{2} - x)

Add a constant to the solution

= \frac{1}{24} (\frac{x ^{2}}{2} - x) + C

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What is the integral of ((x-1))/(24) ?
The integral of ((x-1))/(24) is 1/24 ((x^2)/2-x)+C