What is the integral of 1/(4u) ?

The integral of 1/(4u) is 1/4 ln|u|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(4u)

\int \frac{1}{4 u} d u

\frac{1}{4} ln ∣ u ∣ + C

Solution steps

\int \frac{1}{4 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{4} ln ∣ u ∣

Add a constant to the solution

= \frac{1}{4} ln ∣ u ∣ + C

\int \frac{x - 1}{x ^{2}} e^{x} d x

\int sec^{2} (4 x) tan (4 x) d x

\int cos (\frac{nπ}{L} x) d x

\int \frac{1}{2 x ^{\frac{3}{2}}} d x

\int \frac{9 cos ( θ )}{r} d r