What is the integral of 1/((sin^2(x))) ?

The integral of 1/((sin^2(x))) is -cot(x)+C

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integral of 1/((sin^2(x)))

\int \frac{1}{( sin ^{2} ( x ) )} d x

- cot (x) + C

Solution steps

\int \frac{1}{sin ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{sin ^{2} ( x )} d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

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What is the integral of 1/((sin^2(x))) ?
The integral of 1/((sin^2(x))) is -cot(x)+C