What is the integral of sec(12x)tan(12x) ?

The integral of sec(12x)tan(12x) is 1/12 sec(12x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sec(12x)tan(12x)

\int sec (12 x) tan (12 x) d x

\frac{1}{12} sec (12 x) + C

Solution steps

\int sec (12 x) tan (12 x) d x

Apply u-substitution

: \int \frac{1}{12} d u

= \int \frac{1}{12} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{12} u

Substitute back

u = sec (12 x)

= \frac{1}{12} sec (12 x)

Add a constant to the solution

= \frac{1}{12} sec (12 x) + C

\int - x cos (3 x) d x

\int (x + 1)^{2} \cdot 3^{- x} d x

\int \frac{- 6}{3 x} d x

\int \frac{1}{x ( x ^{n} + a )} d x

What is the integral of sec(12x)tan(12x) ?
The integral of sec(12x)tan(12x) is 1/12 sec(12x)+C