What is the integral of (3x^2+ycos(x)) ?

The integral of (3x^2+ycos(x)) is x^3+ysin(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x^2+ycos(x))

\int (3 x^{2} + y cos (x)) d x

x^{3} + y sin (x) + C

Solution steps

\int 3 x^{2} + y cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x + \int cos (x) y d x

\int 3 x^{2} d x = x^{3}

\int cos (x) y d x = y sin (x)

= x^{3} + y sin (x)

Add a constant to the solution

= x^{3} + y sin (x) + C

\int e^{x} cos (e^{x}) + \frac{2 x + 2}{x ^{2} + 2 x} d x

\int - csc (5 x + 6) cot (5 x + 6) d x

\int (2 sin (x) + 7 sinh (x)) d x

\int \frac{( 4 x ^{2} + x )}{( 8 x ^{3} + 3 x ^{2} ) ^{2}} d x

\int - 6 e^{t} + 3 e^{3 t} d t

What is the integral of (3x^2+ycos(x)) ?
The integral of (3x^2+ycos(x)) is x^3+ysin(x)+C